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eecalpy-0.9.4
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مشاهده بیشترتوضیحات
collection of classes for simple to complex electrical calculations
| ویژگی | مقدار |
|---|---|
| سیستم عامل | - |
| نام فایل | eecalpy-0.9.4 |
| نام | eecalpy |
| نسخه کتابخانه | 0.9.4 |
| نگهدارنده | [] |
| ایمیل نگهدارنده | [] |
| نویسنده | Sebastian Werner |
| ایمیل نویسنده | wese3112@startmail.com |
| آدرس صفحه اصلی | http://github.com/wese3112/eecalpy.git |
| آدرس اینترنتی | https://pypi.org/project/eecalpy/ |
| مجوز | - |
# eecalpy Python module
[](https://badge.fury.io/py/eecalpy)
[](https://travis-ci.org/wese3112/eecalpy)
The *Electrical Engineering Calculations for Python* module is a
collection of classes for simple to complex electrical calculations, with a
special focus on handling tolerances.
**USE AT OWN RISK, I DO NOT GUARANTEE THE CORRECTNESS OF THE CALCULATIONS IN THIS PACKAGE**
## Installation
The ``eecalpy`` package is available on the Python Package Index (PyPI). The package needs Python 3+, you can install it with:
$ pip install eecalpy
## Introduction
Check out the voltage divider below. For both resistors their tolerance and the
temperature coefficient α are given (α in parts per million).
Let's create two variables for them.
>>> r1 = R(resistance=1000, tolerance=0.05, alpha_ppm=250)
>>> r2 = R(2e3, 0.01, 100)
>>> r1; r2
1.0kΩ ± 5.0% (± 50.0Ω) [0.9500 .. 1.0500]kΩ @ 20°C α=250ppm
2.0kΩ ± 1.0% (± 20.0Ω) [1.9800 .. 2.0200]kΩ @ 20°C α=100ppm
The formula for the voltage divider factor is `r1 / (r1 + r2)`. To calculate it use `R.voltage_divider(other_resistor)`:
>>> r1.voltage_divider(r2)
0.33 ± 4.0% [0.3199 .. 0.3465]
You can also use a shorthand notation:
>>> r1 // r2
0.33 ± 4.0% [0.3199 .. 0.3465]
Attention: Do not use the statement `r1 / (r1 + r2)` here, because it would use the tolerance limits
of `r1` twice (addition and division) and therefore yield a false result.
The result above is an instance of the `Factor` class. Now only the voltage is missing.
These are created using `U(voltage, tolerance=0.0)`.
Let's assume the input voltage is 24V with a 1% tolerance the output voltage of the
voltage divider then is:
>>> vin = U(24, 0.01)
>>> vout = r1 // r2 * vin
>>> vout
8.0V ± 5.0% (± 400.0mV) [7.6000 .. 8.4000]V
Note: the statement `vout = vin * r1 // r2` does not work. It's evaluated from left to right, so python first tries `vin * r1` which is not implemented (voltage times resistance), but you can always use parenthesis:
>>> vin * (r1 // r2)
8.0V ± 5.0% (± 400.0mV) [7.6000 .. 8.4000]V
For demonstration, let's calculate some of the voltage divider parameters.
Current through `R1` and `R2` (to GND):
>>> vin / (r1 + r2)
8.01mA ± 3.33% (± 266.81µA) [7.7394 .. 8.2730]mA
Power dissipation of the resistors:
>>> vout**2 / r1
65.46mW ± 21.35% (± 13.97mW) [51.4842 .. 79.4301]mW
>>> (vin - vout)**2 / r2
128.26mW ± 12.3% (± 15.78mW) [112.4776 .. 144.0351]mW
Let's also see how `vout` changes when the ambient temperature is 200°C:
>>> r1.at_T(200) // r2.at_T(200) * vin
8.14V ± 4.97% (± 404.16mV) [7.7359 .. 8.5443]V
`R.at_T(temperature)` is the same as `R.at_temperature(temperature)`.
It returns a new resistor object at the given temperature (in °C).
You can of course also use perfect values, so without the tolerance and
temperature coefficient:
>>> r1 = R(1e3)
>>> r2 = R(2e3)
>>> vin = U(24)
>>> r1; r2; vin
1.0kΩ @ 20°C
2.0kΩ @ 20°C
24.0V
>>> vout = r1 / (r1 + r2) * vin
>>> vout
8.0V
By the way, you can get the series resistance using `+` and the parallel
resistance using `|`:
>>> r1 + r2
3.0kΩ @ 20°C
>>> r1 | r2
666.67Ω @ 20°C
>>> r1 | (R(5e3) + R(3e3)) | r2 # complex statements allowed!
615.38Ω @ 20°C
## Classes
The available classes are:
* Voltage `U(voltage, tolerance=0.0)`
* Resistance `R(resistance, tolerance=0.0, alpha_ppm=None)`
* Current `I(current, tolerance=0.0)`
* Power `P(power, tolerance=0.0)`
* Factor `Factor(factor, tolerance)` (unitless factor, example below)
* squared Voltage (V²) `Usq(voltage, tolerance=0.0)`
* squared Current (A²) `Isq(voltage, tolerance=0.0)`
All classes do have the following members (example when using a voltage):
>>> v1 = U(24, 0.04)
>>> v1
24.0V ± 4.0% (± 960.0mV) [23.0400 .. 24.9600]V
>>> v1.value
24
>>> v1.min
23.04
>>> v1.max
24.96
>>> v1.unit
'V'
A unit can also be created using the `.from_min_max(min, max)` classmethod when
the lower and upper limit is known (min/max):
>>> P.from_min_max(3, 4)
3.5W ± 14.29% (± 500.0mW) [3.0000 .. 4.0000]W
All units feature the add, subtract, multiply and divide operators. The calculation
only works if the result's type is one of the classes above:
This works because the result type is one of the known classes:
>>> U(10) + U(20)
30.0V
>>> I(2e-3) - I(10e-3)
-8.0mA
>>> U(10) * I(2e-3)
20.0mW
>>> U(10) / I(2e-3)
5.0kΩ @ 20°C
>>> U(10) * Factor(2)
20.0V
>>> I(10e-3) * R(150)
1.5V
>>> P(200) / U(5)
40.0A
>>> U(3) * U(3)
9.0V²
>>> U(3)**2 # U squared
9.0V²
>>> U(3)**2 / R(1e3)
9.0mW
This does not work because voltage divided by power is not a known class:
>>> U / P
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: unsupported operand type(s) for /: 'type' and 'type'
نیازمندی
| مقدار | نام |
|---|---|
| - | lark-parser |
نحوه نصب
نصب پکیج whl eecalpy-0.9.4:
pip install eecalpy-0.9.4.whl
نصب پکیج tar.gz eecalpy-0.9.4:
pip install eecalpy-0.9.4.tar.gz