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easypubsub-0.4.3


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توضیحات

A simple wrapper around PyZMQ that provides an easy interface to Publish Subscribe.
ویژگی مقدار
سیستم عامل -
نام فایل easypubsub-0.4.3
نام easypubsub
نسخه کتابخانه 0.4.3
نگهدارنده []
ایمیل نگهدارنده []
نویسنده Matteo Pompili
ایمیل نویسنده -
آدرس صفحه اصلی -
آدرس اینترنتی https://pypi.org/project/easypubsub/
مجوز -
# 🗞️ EasyPubSub [![Documentation Status](https://readthedocs.org/projects/easypubsub/badge/?version=latest)](https://easypubsub.readthedocs.io/en/latest/?badge=latest) [![PyPI](https://img.shields.io/pypi/v/easypubsub)](https://pypi.org/project/easypubsub/) [![License: MIT](https://img.shields.io/badge/license-MIT-brightgreen)](https://github.com/matpompili/easypubsub/blob/main/LICENSE) [![Code style: black](https://img.shields.io/badge/code%20style-black-000000.svg)](https://github.com/psf/black) [![Tests](https://github.com/matpompili/easypubsub/actions/workflows/python-package.yml/badge.svg)](https://github.com/matpompili/easypubsub/actions/workflows/python-package.yml) [![Codacy Code Quality](https://app.codacy.com/project/badge/Grade/80f24926df804a108a568ca640352bd8)](https://www.codacy.com/gh/matpompili/easypubsub/dashboard?utm_source=github.com&utm_medium=referral&utm_content=matpompili/easypubsub&utm_campaign=Badge_Grade) [![Codacy Coverage](https://app.codacy.com/project/badge/Coverage/80f24926df804a108a568ca640352bd8)](https://www.codacy.com/gh/matpompili/easypubsub/dashboard?utm_source=github.com&utm_medium=referral&utm_content=matpompili/easypubsub&utm_campaign=Badge_Coverage) **EasyPubSub** is a simple wrapper around [PyZMQ](https://pyzmq.readthedocs.io/en/latest/) that provides an easy interface to the *PubSub* (Publish-Subscribe) functionality of [ZeroMQ](https://zeromq.org/). In PubSub, a *publisher* publishes a message to a *topic* and a *subscriber* subscribes to that topic and receives the message. In EasyPubSub, publishers and subscribers connect to each other via a *proxy*, which acts as intermediary between them. For more information regarding *PubSub*, see [Wikipedia](https://en.wikipedia.org/wiki/Publish%E2%80%93subscribe_pattern). ## Get started EasyPubSub can be installed via `pip`: ```bash pip install easypubsub ``` ### Proxy Now let's start a proxy (code from `examples/example_proxy.py`): ```python import time from easypubsub.proxy import Proxy PUBLISHERS_ADDRESS = "tcp://127.0.0.1:5555" SUBSCRIBERS_ADDRESS = "tcp://127.0.0.1:5556" proxy = Proxy(PUBLISHERS_ADDRESS, SUBSCRIBERS_ADDRESS) proxy.launch() try: while True: time.sleep(0.1) except KeyboardInterrupt: proxy.stop() ``` This starts a proxy (stoppable with `CTRL-C`) that allows publishers to publish messages to `PUBLISHERS_ADDRESS` and subscribers to subscribe to topics on `SUBSCRIBERS_ADDRESS`. By using a proxy, publishers and subscribers can connect to each other without having to know each other's addresses. ### Publisher Let's create a publisher that every ten seconds announces one random number (code from `examples/example_publisher.py`): ```python import random import time from easypubsub.publisher import Publisher PUBLISHERS_ADDRESS = "tcp://127.0.0.1:5555" PUBLISH_INTERVAL = 10 # seconds. publisher = Publisher("lottery", PUBLISHERS_ADDRESS, default_topic="winning_number") try: while True: publisher.publish(message=random.randint(1, 100)) time.sleep(PUBLISH_INTERVAL) except KeyboardInterrupt: pass ``` ### Subscriber Now we can create a subscriber that prints the winning number every time it receives one (code from `examples/example_subscriber.py`): ```python import time from easypubsub.subscriber import Subscriber SUBSCRIBERS_ADDRESS = "tcp://127.0.0.1:5556" subscriber = Subscriber("lottery_player", SUBSCRIBERS_ADDRESS) try: while True: result = subscriber.receive() if len(result) > 0: print("Received:") for topic, message in result: print(f"{topic}: {message}") else: # No message received. time.sleep(1.0) except KeyboardInterrupt: pass ``` There can be many publishers and subscribers connected to the same proxy, try starting a few of them with different names! For more detailed information, please visit the [documentation](https://easypubsub.readthedocs.io/en/latest/).


نیازمندی

مقدار نام
>=23.2 pyzmq


زبان مورد نیاز

مقدار نام
>=3.8 Python


نحوه نصب


نصب پکیج whl easypubsub-0.4.3:

    pip install easypubsub-0.4.3.whl


نصب پکیج tar.gz easypubsub-0.4.3:

    pip install easypubsub-0.4.3.tar.gz