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توضیحات

Build admin-style views with minimal code

ویژگی	مقدار
سیستم عامل	-
نام فایل	django-fastview-0.1.0
نام	django-fastview
نسخه کتابخانه	0.1.0
نگهدارنده	[]
ایمیل نگهدارنده	[]
نویسنده	Richard Terry
ایمیل نویسنده	code@radiac.net
آدرس صفحه اصلی	https://radiac.net/projects/django-fastview/
آدرس اینترنتی	https://pypi.org/project/django-fastview/
مجوز	BSD

=============== Django Fastview =============== Flexible view system to help you build views quickly. .. image:: https://github.com/radiac/django-fastview/actions/workflows/ci.yml/badge.svg :target: https://github.com/radiac/django-fastview/actions/workflows/ci.yml .. image:: https://codecov.io/gh/radiac/django-fastview/branch/develop/graph/badge.svg?token=5VZNPABZ7E :target: https://codecov.io/gh/radiac/django-fastview .. image:: https://readthedocs.org/projects/django-fastview/badge/?version=latest :target: https://django-fastview.readthedocs.io/en/latest/?badge=latest :alt: Documentation Status Fastview slashes development time for modern hybrid frontends - build comprehensive yet customisable CRUD views in a couple of lines, with built-in HTMX support. * Create a view group to manage models - list, read, create, update and delete views * All views are class-based, so they're quick and easy to customise * Default templates are designed to be customised or replaced to fit your design * Advanced permission system allows fine-grained row-level access control * Built-in support for HTMX (coming soon), inline model formsets and more Note: this is an alpha release; expect feature and API changes in future versions. Check upgrade notes for instructions when upgrading. * Project site: https://radiac.net/projects/django-fastview/ * Documentation: https://django-fastview.readthedocs.io/ * Source code: https://github.com/radiac/django-fastview * Requires Python 3.7 or later and Django 2.2 or later Example ======= Lets write a wiki where anyone can view, add, edit and delete pages: .. code-block:: python # urls.py (for example purposes - normally define the viewgroup in app/views.py) from fastview.viewgroups import ModelViewGroup from fastview.permissions import Public from mywiki.models import Wiki class WikiViewGroup(ModelViewGroup): model = Wiki permission = Public() urlpatterns = [ url(r'^wiki/', WikiViewGroup().include(namespace="wiki")), ] This will create a functioning set of list, detail, create, update and delete views under the ``/wiki/`` path on your site. There are all sorts of things you can do from here: * The views are all based on Django's generic class-based views, so they're easy to customise * Easy and flexible permissions to control who can do what See the `Tutorial`__ in the documentation for more details. __ https://django-fastview.readthedocs.io/en/latest/tutorial/index.html Quickstart ========== 1. Install using pip:: pip install django-fastview 2. Add to ``INSTALLED_APPS``:: INSTALLED_APPS = [ ... "fastview", ] 3. Optional: add the default JavaScript and CSS to your templates or frontend build process. See `Getting Started`__ in the documentation for more details. __ https://django-fastview.readthedocs.io/en/latest/get_started.html Advanced example ---------------- Build a more complex view group with custom view classes and complex access controls: .. code-block:: python # urls.py (for example purposes) from fastview.viewgroups import ModelViewGroup from fastview.permissions import Public, Login, Staff, Owner, Django from myblog.models import Blog from myblog.views import BlogUpdateView, BlogPublishView class BlogViewGroup(ModelViewGroup): model = Blog # Default permission for views - any views without explicit permissions will # require that user is logged in permission = Login() # Make the list view public by reconfiguring it with a call to View.config() list_view = fastview.views.generics.ListView.config( permission=Public(), ) # Make the detail view public by reconfiguring it with the dict shorthand format detail_view = dict( permission=Public(), ) # Override update with a custom view, and limit access to staff or post owners update_view = BlogUpdateView.config( permission=Staff() | Owner("owner"), ) # Use the Django permission framework to manage who can delete Blog objects delete_view = dict( permission=Django("delete"), ) # Add a publish view where only staff can access, but only if it's not their own publish_view = BlogPublishView.config( permission=Staff() & ~Owner("owner"), ) urlpatterns = [ url(r'^blog/', BlogViewGroup().include(namespace="blog")), ] You may then want to create a custom templates at ``templates/myblog/blog/list.html`` and ``templates/myblog/blog/detail.html`` to change the way blog posts are rendered. For more details see the `main documentation`__. __ https://django-fastview.readthedocs.io/ More examples ------------- See Examples in the documentation for more details on these two examples, as well as how you can use fastview to: * configure and customise the views * use permissions to control access to individual database objects * add inline models to your forms * and more

نیازمندی

مقدار	نام
>=2.2	Django

زبان مورد نیاز

مقدار	نام
>=3.7	Python

نحوه نصب

نصب پکیج whl django-fastview-0.1.0:

pip install django-fastview-0.1.0.whl

نصب پکیج tar.gz django-fastview-0.1.0:

pip install django-fastview-0.1.0.tar.gz