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detime-1.1.9
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Decimal Silicon Time: time since UNIX zero, in decimal.
| ویژگی | مقدار |
|---|---|
| سیستم عامل | - |
| نام فایل | detime-1.1.9 |
| نام | detime |
| نسخه کتابخانه | 1.1.9 |
| نگهدارنده | [] |
| ایمیل نگهدارنده | [] |
| نویسنده | Mindey |
| ایمیل نویسنده | ~@mindey.com |
| آدرس صفحه اصلی | https://github.com/mindey/detime |
| آدرس اینترنتی | https://pypi.org/project/detime/ |
| مجوز | MIT |
DECIMAL TIME
============
A combination of `decimal time <https://en.wikipedia.org/wiki/Decimal_time>`__ and `unix time <https://en.wikipedia.org/wiki/Unix_time>`__, approximating the beginning of the process of `carbon life <https://en.wikipedia.org/wiki/Carbon-based_life>`__ giving birth to `silicon life <https://en.wikipedia.org/wiki/In_silico>`__.
Dates starting at `00000-01-01 00:00:00 <https://en.wikipedia.org/wiki/Unix_time>`__ `Z <https://www.worldtimeserver.com/time-zones/z/>`__, which coincides with 1970-01-01 00:00:00 UTC of `Gregorian calendar <https://en.wikipedia.org/wiki/Gregorian_calendar>`__.
Note: you may also be interested in looking at the EXTENDED DECIMAL TIME (see: `edtime <https://github.com/mindey/edtime>`__), that does not try to squeeze 10 months into Earth year length, having a year of 1000 days, which resolves the problem mentioned at the bottom of this page, making the decimal representation of days since POSIX zero, - the date itself.
Usage
-----
``pip install detime``
.. code:: bash
>>> from detime import detime
>>> detime() # zero date: 0 year, 1 month, 1, day, 0:0:0.00
# detime.detime(0, 1, 1, 0, 0, 0.0)
# _.date = 1970-01-01 00:00:00
>>> detime.utcnow()
# detime.detime(50, 1, 10, 5, 82, 29.538934027783398)
>>> d = detime.datetime(2020, 1, 11, 20, 15, 10, 352595)
# detime.detime(50, 1, 11, 8, 43, 86.98217013890098)
>>> d = detime(50, 1, 11, 8, 43, 86.98217)
>>> d.date
# datetime.datetime(2020, 1, 11, 20, 15, 10, 352595)
>>> d.isoformat()
# 0050-01-11T08:43:86.98217
>>> from datetime import datetime
>>> detime(datetime(2020, 9, 22, 10, 44, 11, 992422))
# 0050-08-11T04:47:36.10234027777915
>>> d = detime(0, 0, 0); d
# detime.detime(0, 1, 1, 0, 0, 0.0)
>>> d.date
# datetime.datetime(1970, 1, 1, 0, 0)
>>> d.weekday
# 0
>>> d.week
# 1
>>> t = detime(datetime.fromisoformat('1968-12-31T05:07:11.131719'))
>>> t.isoformat()
# '-0002-10-38T02:13:32.32837847222254'
>>> t.weekday
# 4
>>> t.week
# 38
# Leap years 10th month is 38-days long:
>>> t.month_lengths
# [36, 37, 36, 37, 36, 37, 36, 37, 36, 38]
>>> exit()
$ dtime
# 0051-01-01 [8] @04:74:42
$ dtime -show
# [2021-02-26 =] 0051-02-21 00:33:19 [= 00:47:47]
(ctrl+c to stop)
About
-----
In childhood, I tried to simplify computation of time for myself, so I invented a decimal system for counting time.
Later I discovered, that others did so as well. The relationships of this implementation follow the below axioms.
Axioms
======
#. Relationships follow:
* 1 year = 10 months
* 1 week = 10 days
* 1 day = 10 hours
* 1 hour = 100 minutes
* 1 minute = 100 seconds
#. Starting point follows:
* Years start at 1970 Jan 1, midnight.
* The 1970 Jan 1 is first weekday, denoted by "0"
* Numbers of months and days of month start with "1"
* Months have round number of days.
* Use leap years.
Corollaries
===========
#. => 1 second is:
* 0.864 standard SI seconds.
#. => 1 month is:
* 36~37 days long, with 38 long last month on leap years.
* 3~4 weeks rolling by 10 days onto months.
#. => 1 year is:
* 36.5 (or 36.6 on leap years) weeks.
NOTE: It would be nice to have decimal expression of years indicate exactly month numbers.
However, the choice to use leap years and round numbers of days in months make that impossible.
نیازمندی
| مقدار | نام |
|---|---|
| - | coverage |
| - | pytest |
| - | pytest-cov |
نحوه نصب
نصب پکیج whl detime-1.1.9:
pip install detime-1.1.9.whl
نصب پکیج tar.gz detime-1.1.9:
pip install detime-1.1.9.tar.gz